Question

Need help with a problem from my homework.
Express answer in exact form.

Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)

Answer 1

The answer should be like this

Answer 2

Find the area of of the larger segment by finding the area of the whole circle and subtracting the answer from question 1.

Area of the circle = pi*r^2
Area of the circle = 3.14*8^2 = 301.06

Area of the larger segment = 201.06 - 5.798 = 195.26

Answer 3

The answer needs to actually be like that equation
\[A=(\frac{ [][][] }{ [] }\pi + [][]\sqrt{[]})\]

Answer 4

You just plug that information in...

Answer 5

Im bad at what I do ok? their is a reason I am in summerschool right now

Answer 6

Sorry sorry lemme see...

Answer 7

We know that the triangle formed by the two radii and the chord is
an equilateral triangle, all angles are 60 degrees, which is 1/6 of
360 degrees
Find area inside the 60 degree arc
1%2F6*pi%2A8%5E2 = 35.51
Find the area of the equilateral triangle
1%2F2*8*sqrt%288%5E2-4%5E2%29 = 27.71 sq/in
Find the area of the shape enclosed by the 60 degree arc and the chord
35.51 - 27.71 = 7.8 sq/in
Find the area of the larger segment
pi%2A8%5E2 - 7.8 = 193.26 sq/inches

Answer 8

pi*8^2- 7.8 = 193.26 sq/inches

Answer 9

^^^^^^^short to the point answer