Question

-42s^4 t^6+36s^3 t^5+6s^2 t^4+24st^2/2st^2

Find the quotient

Answer 1

\[\Large \frac{-42s^4 t^6+36s^3 t^5+6s^2 t^4+24st^2}{2st^2}\]
Okay, this is one of the more basic skills in algebra, so pay attention :)
First thing you want to do is deal with the numbers, if you can...
You'll want to divide each of these coefficients
\[\Large \frac{\color{blue}{-42}s^4 t^6+\color{blue}{36}s^3 t^5+\color{blue}{6}s^2 t^4+\color{blue}{24}st^2}{2st^2}\]

By the coefficient in the denominator...
\[\Large \frac{-42s^4 t^6+36s^3 t^5+6s^2 t^4+24st^2}{\color{red}2st^2}\]

Answer 2

but it seems like the awnser would be a small simple one. and not that..? is there any way to like simlify that or something??

Answer 3

We are simplifying it... I'm just showing you the steps... one at a time :)

Answer 4

You there? Divide those coefficients at the numerator (the blue ones) by 2 (the coefficient in the denominator)....
What do you get?

Answer 5

add them all together then divide??

Answer 6

No, just divide... okay, I'll do a simple example, aye? :)
\[\Large \frac{25x^3y^2 -10x^2y^3}{5xy}\]

First thing I'll do is divide the coefficients at the top \[\Large \frac{\color{blue}{25}x^3y^2 -\color{blue}{10}x^2y^3}{5xy}\]
by 5...\[\Large \frac{25x^3y^2 -10x^2y^3}{\color{red}5xy}\]

we get\[\Large \frac{\color{blue}5x^3y^2 -\color{blue}2x^2y^3}{xy}\]
(note how the 5 in the denominator is now gone...)

Next, we divide these x's \[\Large \frac{5\color{blue}{x^3}y^2 -2\color{blue}{x^2}y^3}{xy}\]by the lone x in the denominator.... note that to divide powers of x, you simply subtract their exponents... and since the x in the denominator has no exponent, it's understood to have an exponent of 1. So we subtract 1 from all the exponents of x in the numerator...
\[\Large \frac{5\color{blue}{x^2}y^2 -2\color{blue}{x}y^3}{y}\](Note how the x in the denominator is gone now, too...)


Finally, we divide all the y's in the numerator
\[\Large \frac{5{x^3}\color{blue}{y^2} -2{x^2}\color{blue}{y^3}}{y}\]


following what we did with the x's, we subtract

Answer 7

still confused... soooo..? whats the awnser?