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use the given data to find the minimum sample size required to estimate a population proportion or percentage. Margin of error: seven percentage points, confidence level 95%: from prior study. phat is estimated by the decimal equivalent of 48%. n=?
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remember how to find E? this is just solving that for n
\[E=z\sqrt{\frac{pq}{n}}\] \[\sqrt n=\frac zE \sqrt{pq}\] \[ n=\left(\frac zE \right)^2~pq\]
\[n=\left(\frac {1.96}{.07} \right)^2~.48(.52)\]
and round up ...
would it be 2018
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no
so 196
id go with 196 ... assuming of course i read this correctly :)
since i must round to the nearest integer?
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thank you for the help
youre welcome
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