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Mathematics 10 Online
OpenStudy (bambimonster):

see attachment

OpenStudy (anonymous):

P(G or D) = P(G) + P(D) - P(G and D) Plug in what you know from above and solve for what you want (P(D)).

OpenStudy (bambimonster):

Its 0.35 I submitted the answer. But its wrong. Cos that's what I exactly did

OpenStudy (bambimonster):

Which of the following statement is true ? a G and C are independent b. G and D are independent. c. C and D are independent. D. None of the three pairs of events are independent.

OpenStudy (anonymous):

do you know that everyone purchases something?

OpenStudy (bambimonster):

Sorry I don't really u dear stand your question.

OpenStudy (bambimonster):

*understand

OpenStudy (anonymous):

P(G or C or D) = P(G) + P(C) + P(D) - P(G and C) - P(G and D) - P(C and D) + P(G and C and D). If you knew that everyone bought at least 1 thing then P(G or C or D) = 1 and you could determine P(D) from the equation. for the independence question, you really need P(G), P(C) and P(D). if two events, A & B, are independent, then P(A and B) = P(A)*P(B)

OpenStudy (anonymous):

i think that b/c there are 3 events that P(G or D)= P(G) + P(D) - P(G and D) + P(G and D and C)

OpenStudy (anonymous):

you there?

OpenStudy (bambimonster):

Hi I asked the TA. She said the first formula is correct. So idk. I ll email my prof now. Maybe there is smtg wrong with the system

OpenStudy (anonymous):

i think that b/c there are 3 events that P(G or D)= P(G) + P(D) - P(G and D) + P(G and D and C)

OpenStudy (bambimonster):

So its gonna be 0.34?

OpenStudy (anonymous):

if you draw a venn diagram you'll see why this should be the case|dw:1375290134671:dw|

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