Question

1. Create a third degree polynomial that when divided by x + 2 has a remainder of –4.

2. Create a division of polynomials problem. Demonstrate how this problem would be solved using both long division and synthetic division.

Answer 1

so it should be like f(x)=(x+2)(ax^2+bx+c)-4, you could choose any values for a,b,c, but a cannot be zero. then simplify by removing the brackets.

sorry I'm not sure about the second part :)

Answer 2

i dont understand

Answer 3

have you done remainder theorem?

Answer 4

you need a third degree po;ynomial which has a factor (x + 2)
just as kelvinltr has written :

(x + 2)(ax^2 + bx + c)

then you need a remainder of -4 so you just add -4
and as he said a, b and c can be any number except a = 0

Answer 5

can i just pick like any number for a b and c starting from 1 and up?

Answer 6

yes

Answer 7

you can let a b and c be 1 if you like

Answer 8

for b and c you can put any rational number.. even stuff like -5/2 . For a you could put anything just like that except for 0

Answer 9

for each different value, you'd get a different function

Answer 10

mkay thanks(: