questions/ picture posted
@mathmate
@amistre64
PLEASE CHECK if ALL MY ANSWERS are CORRECT
1,2,3 are ok how did you get Q4's answer?
is it actually 27/36?
if you color in the squares representing event A and the squares for B and count the squares you do not get 19
which is 3/4?
some squares are in both event A and event B. But you only count those squares once.
oh... so then..
so get a crayon and color in all squares where one of the die is a 4 you will get a cross then color all the squares that have a number bigger than 5 how many squares are colored in ?
when u say where one of the die is 4 its all the numbers either in the column 4 or row 4 right?
yes
11 where one die is a 4 &
17 where sum is greater than 5
so is it total 16/36?
4/9 ?
event A OR event B means if either event happens. I just color in each square for A and for B. then count the squares. I get 28 total
oops, i got 28 too
so 28/36 that simplifies
7/9?
yes Q4's answer is 7/9
is Q5 correct?
P(A|B) means prob of A given B "given B" means color in all the squares that are event B from Q2, you know that there are 26 squares colored in. that will be the denominator in P(A|B) (instead of 36) now of the 26 squares that are colored in, how many are event A? that will be the numerator
9???
yes 9 out of the 26 are event A what is P(A|B) ?
why is it 9 out of 26?? and not 36??
P(A) means how many "A squares" out of the total number of squares (= 36) P(A|B) means how many "A squares" out of the "B squares" ? there are 26 B squares. of those 26, 9 are "A squares"
ohh
so.. its just 9/26?
yes
oh ok. that's the answer then.
yes.
also what about these two problems? i know the 2nd part is wrong and i need help getting the right answer, but im not sure about part I. I think its right
I think for part 2 you should multiply each term by the probability of that term before adding them up
.. so wait
like (2-7)^2* (1/3)??? like that?
but is part 1 correct
where did you get 1/3... use the P(x) number given up top. in this case, for x=2 use P(2)= 1/36
i meant 1/36
and then add em up together?
can u do it too so i can make sure its the same answer u get?
part 1. is ok part 2 is the same idea, except you put in (x-7)^2 * P(x) (in part 1 you did x * P(x) )
ok.. in the end i got...
35/6
yes, I think that's ok
ok..
also, how would u make this venn diagram??
like as a sketch what would it look like?
a venn diagram of what ?
Create a Venn diagram that represents the following: In Area 1, senior girls In Area 2, junior girls In Area 3, senior boys In Area 4, junior boys Label each area and title the Venn diagram as well as each of the two circles.
its based on this problem, because i need to solve a problem using the venn diagram so
There are 70 high school students attending the annual Johnson High School junior and senior dance. Of the 70 students attending, 30 of the students are girls, 24 of the students are seniors, and 6 of the girls are seniors.
1. Given that a student is a senior, what is the probability that the student is a girl? Show your work. 2. Given that a student is a girl, what is the probability that she is a junior? Show your work
juniors and seniors would be different boxes (or circles) so start with |dw:1375295981196:dw|
for 1, i got 1/4 for #2, i got: 12/15 ???
or in simplest form: 4/5
no isn't a venn diagram in circles?? it is.
some juniors and some seniors are girls. ditto for boys divide the boxes in half and label the top part girls and the bottom part boys
so what would the venn diagram look like? since its circles..
make it a circle and divide the circle into quarters label the top half of the circle "girls" and bottom half "boys" label the left half "jr" and the right half "sr"
so like how many sections would it have?
|dw:1375296215433:dw|like this??? :(
are my two answers to #1 and #2 correct though?
|dw:1375296294108:dw|or like this??? right?
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