An aqueous solution of glucose is 10%. The volume in which 1 gram-mole of it is dissolved will be: (a)0.9 Litre (b)9 L (c)1.8 L (d)18 L
glucose is dissolved by mass or by volume??question is not clear
This was all given in the question. But I considered % to be by mass and got stuck
is the answer is d?
Sorry, the answer is (c)
look,if you take by mass then 10 gm of glucose is dissolved is 90 gm of sol.now calculate 1 gm-mol of glucose mean 180 gm will need 9X180 gm of solution.now we suppose that the sol is water so 18 gm =22.4 ltrs,so from this sol needed will be 90X22.4 lt
mass of solute=10 g mass of solvent=90g mass of solution will be 100 g
now if we go through the % by vol den 10 vol dissolved in 90 vol of solution.then 22.4 lt=1 gm-mole will have 22.4X9 ltrs,no matter what we take there will be a 22.4somewhere
i m also stuck c this to thomaster.
hey,got this.
we need that, 10 vol(w/V) glucose is present in 100 vol solution 180 vol glucose is present in 1800 vol. now we take in gm mole,so 1800gm=1800 mL=1.8L
neither density is given nor STP conditions are stated, then how volume and mass are equated? Plz do explain this
as there is nothing given,we can take that the solvent is water.because water is a universal solvent.
thanks
thanks to u too
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