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Chemistry 14 Online
OpenStudy (anonymous):

An aqueous solution of glucose is 10%. The volume in which 1 gram-mole of it is dissolved will be: (a)0.9 Litre (b)9 L (c)1.8 L (d)18 L

OpenStudy (anonymous):

glucose is dissolved by mass or by volume??question is not clear

OpenStudy (anonymous):

This was all given in the question. But I considered % to be by mass and got stuck

OpenStudy (anonymous):

is the answer is d?

OpenStudy (anonymous):

Sorry, the answer is (c)

OpenStudy (anonymous):

look,if you take by mass then 10 gm of glucose is dissolved is 90 gm of sol.now calculate 1 gm-mol of glucose mean 180 gm will need 9X180 gm of solution.now we suppose that the sol is water so 18 gm =22.4 ltrs,so from this sol needed will be 90X22.4 lt

OpenStudy (anonymous):

mass of solute=10 g mass of solvent=90g mass of solution will be 100 g

OpenStudy (anonymous):

now if we go through the % by vol den 10 vol dissolved in 90 vol of solution.then 22.4 lt=1 gm-mole will have 22.4X9 ltrs,no matter what we take there will be a 22.4somewhere

OpenStudy (anonymous):

i m also stuck c this to thomaster.

OpenStudy (anonymous):

hey,got this.

OpenStudy (anonymous):

we need that, 10 vol(w/V) glucose is present in 100 vol solution 180 vol glucose is present in 1800 vol. now we take in gm mole,so 1800gm=1800 mL=1.8L

OpenStudy (anonymous):

neither density is given nor STP conditions are stated, then how volume and mass are equated? Plz do explain this

OpenStudy (anonymous):

as there is nothing given,we can take that the solvent is water.because water is a universal solvent.

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

thanks to u too

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