Question

A die is rolled 600 times. The face with six spots appears 112 times. Is the die biased towards that face, or is this just chance variation?
The alternative hypothesis is

a) The die is biased.
b) The chance that the face with six spots appears is greater than 1/6.
c) The chance that the face with six spots appears is equal to 112/600.
d) The proportion of times the face with six spots appears is equal to 112/600.

Answer please! Note: Discard the letter d because i'm sure it is wrong

Answer 1

we could setup a 99% confidence interval

Answer 2

generally its 95% C.I. convention

Answer 3

1/6 \(\pm\) 2.576 sqrt(112*488/600^3)

Answer 4

1.96 then :)

Answer 5

or a Pvalue

Answer 6

1.96 @amistre64

Answer 7

So the letter is?

Answer 8

the letter is whatever we get after the process is finished ...

Answer 9

if you dont understand the process, then ask some questions to learn it

Answer 10

the Pvalue may be related to:

\[\Huge z_{a/2}=\frac{\frac16-\frac{112}{600}}{\sqrt{\frac{112(488)}{600^3}}}\]

Answer 11

1.26 is within 2 sds

Answer 12

A and D are definitely wrong..

Answer 13

it is a wierd question not that i read it again

Answer 14

*now

Answer 15

a 95% confidence interval about the sample is from .155 to .218

1/6 = .167 which falls within the range

Answer 16

Thanks Amistre, Excellent explanation

Answer 17

youre welcome .... but its still a toss between B and C to me

Answer 18

1/6 - 112/600 = -.02 so it is greater than 1/6; which is B

and the experimental prob is 112/600, which is C

Answer 19

kropot72 may help...
i believe is C but not sure..

Answer 20

oh ... "the alternative hypothesis is"; i must be blind today

Answer 21

H1: is equal to 1/6
H2: is not equal to 1/6

Answer 22

the null has to have an equals in it; the alternative is either >,<, or not=

Answer 23

this is the only one id choose for an alternative of the options then

b) The chance that the face with six spots appears is greater than 1/6.

Answer 24

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