Question

WILL GIVE FAN AND MEDAL!

(Attaching Pic)

Answer 1

Start by cross multiplying.

Answer 2

Just cross-multiply.
2x^2=-16x-30
2x^2+16x+30=0

Answer 3

Just someone asked this question xD

Answer 4

Yes yes I did the work but I got up till here:

\[-x^2 - 8x - 15\]

Answer 5

So how do I factor this?

Answer 6

I know the factors are 3 and 5 but are they negative or positive?

Answer 7

Double negative=positive.

Answer 8

wait u divide 2 by (2x^2+16x+30) than u get x^2+8x+15 which is (x+5)(x+3)=0 than u do x+5=0 and x+3=0 which is x=-3,-5

Answer 9

Yes but C is -15 so that is not possible.

Answer 10

x^2-8x-15
x^2-5x+3x-15
x(x-5)-3(x-5)
(x-5)(x-3)

Answer 11

No the 2 got cancelled when I cross multiplied:

\[\frac{ 2x }{ 2(8x + 15) } = \frac{ -1 }{ x }\]

Answer 12

\( -1(16x + 30) = 2x (x)\)

\(-16x - 30 = 2x^2 \)

\(2x^2 + 16x + 30 = 0\)

\(x^2 + 8x + 15 = 0\)

\((x + 3)(x + 5) = 0 \)

\(x + 3 = 0\) or \(x + 5 = 0\)

\(x = -3\) or \(x = -5 \)

Answer 13

But don't I cancel out the like terms when I cross multiplied?

Answer 14

nono
dont cancel 2

Answer 15

Hmm... ok then

Answer 16

i mean if u cancel 2 ull still get same answer

Answer 17

Yes but it wouldn't work out because -3 and -5 do not make -15

Answer 18

@JA1 You really have an equation, so you have this:

\(-x^2 - 8x - 15 = 0\)

Multiply both sides by -1:

\(x^2 + 8x + 15 = 0\)

Now you can factor as I did above using factors 3 and 5.

Answer 19

because x^2=-8x-15 so u move it to other side and gets x^2+8x+15=0

Answer 20

O.M.G.

Answer 21

I am so shortsighted <_<

Answer 22

I understand now, I need to make it so instead of making x^2 negative I can simply make the other side positive....

Answer 23

yes..

Answer 24

OMG thank you so much xD because of that I got a 90 on my test

Answer 25

You both deserve medls but I only have one D:

Answer 26

dont ever move variable to toher side because it gets confusing

Answer 27

Ah I see...I alwyas mess it up xD well thanks bunch

Answer 28

good bye

Answer 29

Bye bye