Question

limit as x approaches -6 when f(x)=(21-x)^5/3

Answer 1

just substitute -6 in place of x

Answer 2

it's (21-(-6))^5/3=27^5/3

Answer 3

then apply the property:
\[c^{\frac{ a }{ b }}=\sqrt[b]{c^a}\]

Answer 4

so it's \[\sqrt[3]{27^5}\]

Answer 5

Oh, that makes alot of sense. Thanks

Answer 6

so \[\sqrt[3]{27^3*27^2}=\sqrt[3]{27^3}*\sqrt[3]{729}=27*9=243\]