Points P and Q are on a hillside which is at a 35 degree angle of elevation. The points are 107 feet apart, with P downhill from Q, and both downhill from a balloon. The angle of elevation to the balloon as seen at P is 62 degrees, from Q it is 71 degrees. Find the distance from Q to the balloon. Round your final answer to 4 decimal places.

Question

anonymous · Answer

so do you use llaw of sine?

anonymous · Answer

it did not work

anonymous · Answer

http://imageshack.us/photo/my-images/7/39201112259am.png/

anonymous · Answer

this is a picture of it but trying to solve it is the problem..click on the link

anonymous · Answer

didyou find the pic

radar · Answer

The picture is good.  Since the line between P and Q is at an angle of 32 degrees, then the angles of elevation observed at P and Q need to be adjusted to get the angle within the triangle PQB (b  for balloon)  The angles will be reduced by 32 degrees|dw:1375327648084:dw| The elevation angle of 62 degrees has to be reduced by 32 degrees giving you an angle of 30 degrees for the angle within the triangle at P.

The angle of elevation at Q also has to be reduced by 32 degrees or 71 - 32 or 39 degrees at Q outside of the triangle.  To get the angle within the triangle at Q (the interior angle) you will subtract the 39 from 180 getting 141 degrees.  Since the triangle angles must total 180 degrees, you can find the 3rd angle (at the balloon) by subtracting the sum of the 141 and the 30 degree angles from 180 degrees for an angle of 9 degrees.  So now you have all three angles and one side|dw:1375328340157:dw|  The picture shows the side to be 60 meters.  Now use the Law of sines.|dw:1375328575013:dw|