Question

Medal will be given.

Answer 1

Identify whether the series summation of 8 open parentheses 5 over 6 close parentheses to the I minus 1 power from 1 to infinity is a convergent or divergent geometric series and find the sum, if possible.

This is a convergent geometric series. The sum is 48.

This is a divergent geometric series. The sum is 48.

This is a convergent geometric series. The sum cannot be found.

This is a divergent geometric series. The sum cannot be found.

Answer 2

\[\sum_{i=1}^{infinity}8(5/6)^{i=1}\]

Answer 3

to see if its convergent or divergent... find r and if r<1 then convergent.... if r>1 then divergent. if convergent use formula a/(1-r) and get the sum

Answer 4

lol I have no idea what to do

Answer 5

\[\sum_{0}^{\infty} a _{n}(r)^n\]

Answer 6

so what is your r value?? use the series example i gave you and look at ur series

Answer 7

Ok, so it is divergent

Answer 8

after you find the r value.... see if it is less than or greater than 1

Answer 9

less than

Answer 10

so if its less than 1 then it is r<1 and therefore convergent

Answer 11

so if its convergent you can use the formula... \[\frac{ a ^{n} }{1-r}\]

Answer 12

Ok so the answer is A or C

Answer 13

yup.... so can you find the sum using the formula above?

Answer 14

so C

Answer 15

\[\frac{ 8 }{ 1-\frac{ 5 }{ 6 } }\]

Answer 16

I got 48 ty

Answer 17

http://www.wolframalpha.com/input/?i=series+8%285%2F6%29%5En+from+0+to+infinity your welcome.... you can use wolfram alpha as well