expand the log expression; logb(57/74)
\[\log_b(\frac{A}{B})=\log_b(A)-\log_b(B)\]
would that be under a radical ?
following @satellite73 's formula there, what is A and what is B in your problem?
And I don't believe it would be under a radical.
errr the square root sign
I don't see a square root sign? O_o
1/2logb57+1/2logb74 1/2logb57-1/2logb74 \[\sqrt{logb-\log74}\] logb1/2(57-74) are my answer choices
oh, is your problem \(\large \log_b \sqrt{\frac{57}{74}} \)
yes
Oh okay. This can be solved like.. \[\large \log_b \left(\frac{A}{B}\right)^c = c \log_b A - c \log_b B\]
in this case, your "c" or your power will be 1/2 as we change the square root into a "power" format. Then we can just simply use our log identities.
so 1/2logb57-1/2logb74
Yess good job :D
but couldnt it alos be d?
mmhmm.
Nevermind. the "1/2" would come before the log b... the format of that solution statement is wrong. Therefore it cannot be D.
oh yea i get it. ive never seen the 1/2 behind the log
can you help me with one more thing?
\[\large \log_b\left(\frac{A}{B}\right)^c = c \cdot [\log_b (A) - \log_b (B)]\]
That means \(c\log(A) - c\log(B)\)
Sure thing.
i know the answer is b or d but idk how to zoom in on my calculator to try to see the numbers
Which problem are we looking at? Unfortunately i cannot help you solve all of them because that would be violating the code of conduct of OS.
oh im sorry i only meant to send you a screenshot but question 13
Alriiighty :)
yea . idk how to zoom in
here it is
Oh, you don't need to zoom in,you need to zoom out.
but i have to see which equation so i have to see the #'s
Do you recall that \(\large \ln(x) = \frac{1}{x}\)?
yes sir
the answer is d?
So we can immediately eliminate the first choice,since that repr
represnts a parabola* and yes :) you are right.
thank you !
no problemooo
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