f(x) = x2 + 3; g(x) = sqrt(x - 2) Find f(g(x)).
\[\large f(x) = x^2 +3\]\[\large g(x) = \sqrt{x-2}\] so replace all the x's in f(x) with the function of g(x). \[\large f(g(x)) = (\sqrt{x-2})^2 +3 \] When you square a square root, the square root and the square cancel eachother out.
Can you finish solving this now? :)
They don't necessarily cancel each other out, but when you take the product of two square roots, it becomes an integer.
i might be helpful to take an intermediate step maybe not \[f(g(x))=f(\sqrt{x-2})\] may help
replace the general \(g(x)\) by the specific one you have in this case then replace the \(x\) in \(f(x)=x^2+3\) by \(\sqrt{x-2}\)
also helpful not to think of \(x\) when you do this \[f(\diamondsuit)=\diamondsuit^2 +3\] replace \(\diamondsuit\) by \(\sqrt{x-2}\)
x+1 answer
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