Question

what is the solution to the equation log3*x - log3*2 = 2


a. x = 18

b. x = 12

c. x = 9/2

d. x = 4/3

Answer 1

\[\large \log_3x-\log_32=2\]Using rules of logarithms allows us to combine the logs like so,
\[\large \log_3\left(\frac{x}{2}\right)=2\]From here we can rewrite it in exponential form, let me know if this step is confusing.\[\large 3^2=\frac{x}{2}\]
From here, do you understand how to solve for x? :)

Answer 2

@zepdrix im sorry I don't :/

Answer 3

Hmm it looks like the left side gives us 9 since 3 squared is 3x3.

\[\large 9=\frac{x}{2}\]
Multiplying both sides by 2 will put it in the form x=
which is what we want :)

Answer 4

so its c?

Answer 5

@zepdrix

Answer 6

Hmm multiplying by 2 gives us,\[\large 9\cdot2=\frac{x}{\cancel2}\cdot \cancel2\]
Which simplifies to,\[\large 18=x\]

Answer 7

Oh okay! thanks a lot! I really appreciate the help :)