Question

Why do I never get a reply to any of my questions?

Answer 1

whats your question?

Answer 2

I'v had a lot in the past 2 hours :/

Answer 3

well lets start banging them out bro

Answer 4

You are amazing, Ill start typing them out

Answer 5

ok if i cant answer them i will try and get someone on here who can

Answer 6

so whats the first question

Answer 7

Part 1 Is the following equation true?

Part 2 Use complete sentences to explain the properties used in making your decision.

log3 x + 1/2 log3 y - 2 log3 z = log3 x^4 square root y/z^2

Answer 8

sorry I had to type it out

Answer 9

thts alright but crap i haven't learned logs yet lets see if someone is avaliable alright we got two admins in here lets see if they know about this @Mertsj @thomaster

Answer 10

@satellite73

Answer 11

sounds good to me, I just appreciate you answering

Answer 12

dude i have fun doin this i just wish i was better equiped in the mind for this or i would be having a blast i'm still in algebra1

Answer 13

how old are you? I found this site about a week or so ago and it seems like a great place to come for help but its difficult to get people to reply.

Answer 14

@skullpatrol could u answer this

Answer 15

i'm 15 and i have been using this for a while but never bothered to make an account till monday night

Answer 16

Nice, well just know that I appreciate the attempt!

Answer 17

hey anything to help but i dont know if anyone is gonna help this is weird bump ur question back up to the top

Answer 18

What's the question?

Answer 19

what question?

Answer 20

\[\log(x)+\frac{1}{2}\log(y)-2\log(z)\]becomes
\[\log(x)+\log(\sqrt{y})-\log(z^2)\] as the coefficients come inside as exponents

Answer 21

then the sum becomes a produce giving
\[\log(x\sqrt{y})-\log(z^2)\] and the subtraction becomes a division
final answer is
\[\log(\frac{x\sqrt{y}}{z^2})\]

Answer 22

actually the sum becomes a PRODUCT
produce at aisle 8

Answer 23

http://openstudy.com/study#/updates/51f9bec7e4b06e6a116f0f6c