Question

Please help with this easy question! I need to find x and y from these 2 equations:
e^-y * 2x = 0
2ye^-y - e^-y(y^2) = 0

I already found x=0 by solving for x in the first equation. and then i plugged in 0 for x into the 2nd equation and I simplified the equation to ye^-y(2-ye^-y)=0 but im stuck here..
@amistre64

Answer 1

oh it has to be both?

Answer 2

there is no \(x\) in the second equation

Answer 3

@satellite73 im sorry, 2nd equation: 2ye^-y - e^-y(x^2+y^2)=0. I plugged in 0 for x and I simplified it to ye^-y(2-ye^-y)=0

Answer 4

Im trying to get the critical points right now and I need to find x and y from these 2 equations that I obtained by taking the partial derivatives

Answer 5

so you end up with
\[2ye^{-y}-y^2e^{-y}=0\] right?

Answer 6

yes

Answer 7

then i factored out ye^-y

Answer 8

ok then factor out the \(e^{-y}\) or just ignore it because it is never zero, and solve
\[y-y^2=0\]

Answer 9

oops rather
\[2y-y^2=0\]

Answer 10

should be real easy now right?

Answer 11

Yes thank you!

Answer 12

yw