Mathematics
7 Online
OpenStudy (anonymous):
how would you factor this ? 20x-8y+12?
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OpenStudy (anonymous):
each term has a common factor of \(4\) so "factor it out"
that is the best you can do
OpenStudy (anonymous):
i.e. put a 4 outside of some parentheses
\[4(something)\]
OpenStudy (anonymous):
so it would be 4(5x-2y+3)?
OpenStudy (anonymous):
why yes
OpenStudy (anonymous):
hell yes omg :D im so proud of myself
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OpenStudy (anonymous):
yeah by the end of the evening you will be an math whiz
OpenStudy (anonymous):
i hope and its night over here its 12:14 am lol
OpenStudy (anonymous):
ok by 3 a.m. then
OpenStudy (anonymous):
it is night over here too
past my bedtime in fact
OpenStudy (anonymous):
lol i hope i have to pas this practise thing //:
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OpenStudy (anonymous):
aw okay good night then :)
OpenStudy (anonymous):
i just said it was past my bedtime
not going
OpenStudy (anonymous):
lol yay cause sadly i still need your help :P sorry
OpenStudy (anonymous):
once @satellite73 passes his bed-time, he can't fall asleep.
OpenStudy (anonymous):
looks like you are doing fine on your own
what is next?
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OpenStudy (anonymous):
(x-10)(x+4)=0 @satellite73 idk how to do this //;
OpenStudy (anonymous):
set each factor equal to zero and solve
OpenStudy (anonymous):
for the first one you get
\(x-10=0\) and so \(x=10\)
can you do the second one?
OpenStudy (anonymous):
i.e. can you solve
\[x+4=0\] takes on step
OpenStudy (anonymous):
one step
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OpenStudy (anonymous):
x=4
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
\(x+4=0\) subtract \(4\) from both sides
OpenStudy (anonymous):
\[x+4=0\\x+4-4=0-4\\x=-4\]
OpenStudy (anonymous):
ok so its -4
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OpenStudy (anonymous):
yes, so you get two answers \(x=10\) or \(x=-4\)
OpenStudy (anonymous):
-4,10?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
solve (3x+5)(2x-7)=0 @satellite73 help please last one im almost done /"
OpenStudy (anonymous):
ok here we go
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OpenStudy (anonymous):
set \(3x+5=0\) first and solve for \(x\)
subtract \(5\) from both sides and get
\[3x=-5\] then what?
OpenStudy (anonymous):
if it is not clear let me know
OpenStudy (anonymous):
ok i got that part
OpenStudy (anonymous):
then the other side would be 2x=7
OpenStudy (anonymous):
i mean is it clear that if \(3x=-5\) then \(x=-\frac{5}{3}\) ?
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OpenStudy (anonymous):
so it would be -5/3, 7/2?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
you done?
OpenStudy (anonymous):
i failed it
OpenStudy (anonymous):
i got a 70 and was supposed to get a 80
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OpenStudy (anonymous):
damn
OpenStudy (anonymous):
can you do it again? i am fairy sure the problems we did together were right
in fact i am positive
OpenStudy (anonymous):
i know they were all right but the ones i did alone D:
OpenStudy (anonymous):
damn
can you try again tomorrow?
OpenStudy (anonymous):
i cant it was a test thingy now i have to do the practices
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OpenStudy (anonymous):
wow
good luck, i bet you can do them now in any case
OpenStudy (anonymous):
yeah thank you for your help you are very sweet C: