Question

can any one tell me about bisection method of numerical analysis

Answer 1

first of all the values of a and b (the extreme values of the interval within which the root lies must be found out)
then find (a+b)/2

Answer 2

now you have two different intervals within which the root may lie viz
(a,(a+b)/2) ) and ((a+b)/2),b
now you have to find f((a+b)/2)
if the sign of f((a+b)/2) be the same as that of say f(a) but different from f(b)

then the interval (a, (a+b)/2) is discarded
and you have to bisect the new interval ((a+b)/2),b)

Answer 3

agin the new point will be ((a+b)/2 +b)/2 =(a+3b)/4

so the new interval will be ((a+b)/2),(a+3b)/4 ) and ((a+3b)/4,b)

Answer 4

how many iteration can b done how i know this

Answer 5

agian find f((a+3b)/4) and note whether it matches with the sign of f((a+b/2) or with f(b)

Answer 6

discard the suitable interval
and continue the iteration

Answer 7

you will continue the iteration as long as the two extremes are very close to each other
(as per the number of decimal digits required )

Answer 8

for 10^-3 how many iterations can be required

Answer 9

it also depends how close your initial interval is

Answer 10

you have to go continuing with the iteration as long as the new values of a and b are matching each other at least upto 3 places of decimal
but for being more sure continue the iteration till it matches to 4 places of decimal

Answer 11

what the bisection method? is it the eulers method for finding roots?

Answer 12

@dan815 look up

Answer 13

:)