Question

See attatched Help :)

Answer 1

Find the lowest common denominator

Answer 2

We have :
\[\frac 6{8y+8}=\frac{6}{8(y+1)}=\frac{3}{4(y+1)}\]
And :
\[\frac{y+5}{6y^2-6}=\frac{y+5}{6(y^2-1)}=\frac{y+5}{6(y-1)(y+1)}\]

Can you now determine the lowest common denominator ?

Answer 3

24y^2?

Answer 4

24(y^2-1)
or 24(y^2-1)(y+1)

Answer 5

...

Answer 6

Look, it is very simple !
First, we have the numbers 4 in the 1st fraction and 6 in the 2nd question, the lowest common multiple between them is 12 (not 24) ok ?
Then, we have y+1 in the 1st and (y+1)(y-1) in the 2nd, so the lowest common multiple is (y+1)(y-1).

We conclude that the lowest common denominator is :
\[12(y+1)(y-1)\]

Answer 7

Sorry I am obnoxiously awful at math, thank you so much!