Question

If you work for an hourly wage, your gross pay is a function of the number of hours that you work. Your hourly wage is $8 per hour. Assuming you work 40 hours per week, what is the practical domain and the practical range of the function?
a.

The practical domain is 0 through 8. The practical range is 0 through 32.
b.

The practical domain is 0 through 320. The practical range is 0 through 40.
c.

The practical domain is 0 through 40. The practical range is 0 through 320.
d.

The practical domain is 0 through 32. The practical range is 0 through 8.

Answer 1

@Dahlioz

Answer 2

First, let's define practical domain and range; A function is a mathematical relationship where a value of "x" has one value of "y." Though there can only be one "y" assigned to an "x," multiple "x" values can be attached to the same "y." The possible values of "x" is called the domain. The possible values of "y" is called the range. Theoretical domains and ranges deal with all possible solutions. Practical domains and ranges narrow the solution sets to be realistic within defined parameters.

Answer 3

woah that was alot.

Answer 4

sorry I do not understand

Answer 5

If x= hourly wage and y= money earned, the practical domain of the function= the possible values of y, and the practical range= the possible values of x

Answer 6

The practical range of the function would simply be the 0 through the assigned value of x. (8). The practical domain would be 0 through the assigned number of hours worked multiplied by assigned hourly wage; 40*8=320

Answer 7

Do you understand?

Answer 8

@xxkerstie.bbyxx Basically what the term 'Practical' here means as @Dahlioz mentioned is the REAL LIFE interpretation of the function. Normally we could have the domain of 'x' as all real numbers and the range be all real numbers. But since our 'x' is the number of hours worked and the 'y' the total pay, would it really make sense to possibly have worked NEGATIVE number of hours or NEGATIVE total pay? This is why we must restrict the domain and range such that it only interprets realistic 'x' values to realistic 'y' values. Here our domain, x, is the number of hours. We know we can't have negative number of hours hence our domain would atleast be \(\bf x \ge 0\). But at the moment, our domain implies that 'x' can get infinity large, but she can't work an infinite number of hours?! So what should the domain be limited to? I'll leave that to you since that information is given in the question ;].

Now with range, you can't earn a negative amount of money so once again our range should be atleast \(\bf y \ge 0\). But this also implies that one can make an infinite amount of money since y is not restricted! But we know that in real life you can't earn that much money can you? So we must limit our range to the amount she earns in those 40 hours a week. We know she makes 8 dollars every hours and works 40 hours a week so you should be able to work out how much she is making in TOTAL and so you can limit the range appropriately ;]

@xxkerstie.bbyxx

Answer 9

Time is always on the bottom axis. So, hours would be on the x-axis and wage would be on the y-axis. Since they work 40 hours a week and based on your domain/range choices, we can assume that the domain (x-values) is in hours, therefore the wage is the y-values. Also, since they make $8 an hour no matter which hour they work, that will not be your y-values.
Instead, they want how much money that person has made total over the 40 hours. So, you need to add 8 units up for every one unit right you go. If you go right 40 times using this process, you get 8x40, which is 320.
So, your x-values domain over 0-40 and your y-values range from 0-320

Answer 10

Restriction is you can not work more than 40 hours and that your maximum pay is 320 for the week.