Help!! will give medal
Finish the proof that ∠AED≅∠ACB
Given:BC≅DE
Statements Reasons
1)BC≅DE 1)Given
2)∠BAC≅∠DAE 2)???????
3)CB is perpendicular to AE 3)Given
ED is perpendicular to AC 4) def of perpendicular
4)∠ABC and ∠ADE are rt ∠ lines
5)∠ABC≅∠ADE 5)Right angle thm
6)????????????? 6)???????????
7))∠AED≅∠ACB 7)??????????
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OpenStudy (anonymous):
|dw:1375375921484:dw|
OpenStudy (anonymous):
@heather040200 Sorry but it doesn't look like BAC = DAE for 2). Are you sure that is the case or is the diagram a bit off?
OpenStudy (anonymous):
yes I am sure @genius12 that one is given to me
OpenStudy (anonymous):
the diagram could be off I had to draw it
OpenStudy (anonymous):
@stgreen @Hero @robtobey
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OpenStudy (anonymous):
|dw:1375373410974:dw|
OpenStudy (anonymous):
????
OpenStudy (anonymous):
Let <DAE=X
<ADE=90
<AED=90-X (1)
<ABC=90
<<ACB=90-X (2)
From (1) & (2)
<AED=<ACD
OpenStudy (anonymous):
CORRECTION
<A E D=<A C B
OpenStudy (anonymous):
Ok but I need to pretty much fill in the blanks......the reasons should be postulates or theorems
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OpenStudy (anonymous):
@Preetha
OpenStudy (anonymous):
@magbak
OpenStudy (magbak):
I am working on it
OpenStudy (anonymous):
k thanks :)
OpenStudy (magbak):
Are their any options.
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OpenStudy (anonymous):
<BAC=<EAD (COMMON)
OpenStudy (anonymous):
sadly no I am just given that
I just don't kno what postates or theorems to use
OpenStudy (magbak):
I know the answers but I am a little rusty with my theorems and postulates and axioms .
OpenStudy (anonymous):
triangles are similar
OpenStudy (anonymous):
OK
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OpenStudy (magbak):
No he is wrong.
OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
@adilalvi
OpenStudy (magbak):
2) they are the same angle. just writen in a different way.
Sorry but that is all that I know.
OpenStudy (magbak):
Got to go hope I helped bye.
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