Question

For Module 6, solve the following system of equations by graphing, substitution,or elimination
x-y=10
2x+y=2
For Module 7, simplify the following polynomials:
(z+y)^2
(x-y)^2
(x+y)(x-y)

Answer 1

let x=n+5
let y=n-5

Answer 2

and of course "simplify" is a poor word to use inthe other one

Answer 3

wht?

Answer 4

i wrote:

let x=n+5
let y=n-5

:/

Answer 5

is that the answer

Answer 6

no, the answer is the results you get after substituting that into the setup ....

Answer 7

can u help me solve it
and which question is this

Answer 8

its the question that deals with subtitution .... or any of the other methods mentioned in it

Answer 9

x-y=10
2x+y=2

let x=n+5
let y=n-5

(n+5)-(n-5)=10
2(n+5)+(n-5)=2

now solve for n

Answer 10

okay so how u solve n

Answer 11

solving 1 equation for 1 variable should have been gone over prior to asking you to solve for multiple equations in multiple variables .... if you have not learned how to collect like terms and such by now you may want to review past material.

Answer 12

I will use the elimination method

x - y = 10
2x + y = 2
----------add
3x = 12
x = 4

now sub 4 in for x in either of the original equations
2x + y = 2
2(4) + y = 2
8 + y = 2
y = 2 - 8
y = -6

check...
x - y = 10
4 - (-6) = 10
4 + 6 = 10
10 = 10 (correct)

x = 4 and y = -6

================
(z + y)^2 =
(z + y)(z + y) =
use the FOIL method
F - multiply the first terms in each set ....z * z = z^2
O - multiply outside terms in each set ...z * y = zy
I - multiply inside terms in each set ...y * z = zy
L - multiply last terms in each set...y * y = y^2

now put them all together
z^2 + zy + zy + y^2
z^2 + 2zy + y^2

your other problems can be solved the same way :)