Question

Y > -3x + 3
Y < ½ + 3
i need help Algebracaching

Answer 1

y>-3x+3
y+3x>3 ...(1)
y<1/2+3 ...(2)
consider y+3 x=3
3 x=3-y
\[x=\frac{ 3-y }{ 3 }\]
when y=0
\[x=\frac{ 3-0 }{ 3 }=1\]
when y=3
\[x=\frac{ 3-3 }{ 3 }=0\]
draw the graph

put x=0,y=0 in (1)
0+0>3
which is impossible.
hence origin does not lie on the graph.
put x=0,y=0 in (2)
Hence origin lies on the graph
feasible region is the shaded region.

Answer 2

so whats the answer

Answer 3

the whole shaded region.
actually there are infinite solutions in this region
take any point in this region.

Answer 4

ok thank you so much

Answer 5

yw