Question

you roll 2 dice. what is the probability that the sum of the dice is greater than 6 and 1 die shows a 3? A 6 x 6 table of dice outcome will help you to answer this question.

Answer 1

The sample space has 36 possible combinations of numbers. These can be set out in column form as follows:
6,6 5,6 4,6 3,6 2,6 1,6
6,5 5,5 4,5 3,5 2,5 1,5
6,4 5,4 4,4 3,4 2,4 1,4
6,3 5,3 4,3 3,3 2,3 1,3
6,2 5,2 4,2 3,2 2,2 1,2
6,1 5,1 4,1 3,1 2,1 1,1

Answer 2

i still dont understand :(

Answer 3

8/36?

Answer 4

First make a list of all the outcomes on the table where one die shows a 3. Can you do that and post the result?

Answer 5

1:3 2:3 3:3 3:4 3:5 3:6
3:1 3:2 3:3 3:4 3:5 3:6

Answer 6

You have written 3, 3 twice, but that doesn't matter in this case. Now count up the number of outcomes in your list where the sum of the two numbers is greater than 6. Please post you result.

Answer 7

8 times,if you include 3,3 twice
7 times if you include it once

Answer 8

But 3 + 3 = 6 and is therefore not counted, the reason being that 6 is not greater than 6. Only the sums which are 7 or higher are to be counted.

Answer 9

6 times

Answer 10

Correct, there are six outcomes where the sum of the dice is greater than 6 and 1 die shows a 3. Therefore the required probability is 6 divided by the total number of possible outcomes:
\[\frac{6}{36}=\ ?\ when\ simplified\]

Answer 11

1/6

Answer 12

Well done! You are correct :)

Answer 13

yay! thank you!!

Answer 14

You're welcome :)