If someone can please help me (Don't give me the answer) If 1.6 moles of an ideal gas are at a temperature of 25°C and a pressure of 0.91 atm Hg, what volume would the gas occupy, in liters?
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Apply the formula PV=nRT i hope
Exactly. Can you solve PV=nRT for V?
; -; Uh... V= Pn/RT?
V= nRT/P
No, you only need to divide by V so P=nRT/P. Then jjust plug in the numbers. remember you need the temperature in kelvin
If 1.6 moles of an ideal gas are at a temperature of 25°C and a pressure of 0.91 atm Hg, what volume would the gas occupy, in liters? Okay so P = 0.91 T= 25°C n= ??? R= ???
n is the number of moles. R is the gas constant, you can look for it on google. remember T is T=(25+273.15)k
Okay so... How do I fined the gas content or is it the same as the moles?
\[0.0821 L atm mol ^{-1} /K ^{-1}\]
e__e okay so the answer will be 43L?
yep
Thank you! c: <3
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