solve abs(x+2)<=8+abs(2x-4)
|dw:1375383800159:dw| so always
statement is true for all x in the real numbers
how about solve analytically, please
hmmm so let's check the vertices you have 2 absolute values, so you have 2 vertices what makes |x+2| to 0? well x = -2, one vertex what makes |2x-4| to 0? well x = 2, 2nd vertex so we end up with 3 intervals to values against |dw:1375384559250:dw|
where's the 8?
\(\bf \textit{left side -, right side -}\\ -x-2 \le 8-2x+4\\ \textit{setting x = -3}\\ 3-2 \le 8+6+4 \textit{ \# true, thus is an answer}\)
ohh, the 8 is a shift, but in the graph is not used, just the vertices is all I used and the graph the expression itself
i see what you're doing...
and doing the test for the the 2nd interval and 3rd interval with - and + and + and + for the expressions, will yield all of them are true, thus are solutions
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