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Mathematics 23 Online
OpenStudy (anonymous):

250e^(2/3In2)

OpenStudy (anonymous):

yeah...

OpenStudy (anonymous):

\[\frac{2}{3}\ln(2)=\ln(2^{\frac{2}{3}})\] is a start

OpenStudy (anonymous):

then \[e^{\ln(x)}=x\] should help

OpenStudy (anonymous):

correction 650?

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