You have a 3-card deck containing a king, a queen, and a jack. You draw a random card, then put it back you draw a random second card. Use a tree diagram to calculate the probability that you draw exactly 1 jack.
Are you able to do the following:? Draw a tree with 3 branches: J, Q, and K. From each of these branches, draw the same 3 (J, Q, and K) branches. The first level is the "first pick". The second level is the "second pick". You will have as an end result, nine branches, all of which are equally likely. Count the branches that have exactly ONE Jack (either as first or second). Call that number "x". Your probability is "x" over 9.
okay so 3/9?
|dw:1375389511855:dw|Trace each branch from the beginning and count the number of J's in it. Do this for all 9 branches. How many have only one "j".
4?
Your branches, in order look like: 1) J J 2) J Q 3) J K 4) Q J 5) Q Q 6) Q K 7) K J 8) K Q 9) K K That gives 4 branches having exactly one jack. Branches (2, 3, 4, and 7) Probability is 4/9
okay thank you so much :)
uw!
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