Question

In the figure, the circle is inscribed in the equilateral triangle. If the diameter of the circle is 2, what is the sum of the shaded area?

Answer 1

\[(A) 3\sqrt{3} -\]
\[(B) 3\sqrt{3} -4\]
\[(C) 3\sqrt{3} - \frac{ 3\pi }{ 2 }\]
\[(D) 6\sqrt{3} -\frac{ 3\pi }{ 2 }\]
\[(E) 108 -\]

Answer 2

\[(E) 108-\pi \]

Answer 3

The shaded region is equal to the triangle - the circle.

Answer 4

We know the diameter (+radius) of the circle, and the circle's A(r)=pi r^2

Answer 5

2 diameter is 1 radius,

circle = pi* (1)^2, pi * 1, = pi

Answer 6

so know we have

the triangle - the circle,

the triangle - pi

Answer 7

got any tricks 2find the triangle and finish ?