Question

help pleaseeeee

Answer 1

@primeralph @satellite73

Answer 2

center is \((-3,0)\) so you know it will look like
\[\frac{(x+3)^2}{a^2}+\frac{y^2}{b^2}=1\]

Answer 3

from the center up is 5 units, making \(b=5\) and from the center to the sides is \(3\) units, giving \(a=3\)

Answer 4

is that the same formula you would use to write it in standard form?

Answer 5

yes, you need the center, and also \(a\) and \(b\)
standard form is
\[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\] for an ellipse with center \((h,k)\)
final answer should be
\[\frac{(x+3)^2}{9}+\frac{y^2}{25}=1\]

Answer 6

lets check it

Answer 7

http://www.wolframalpha.com/input/?i=+%28x%2B3%29^2%2F9%2By^2%2F25%3D1

looks pretty good !