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Chemistry 15 Online
OpenStudy (anonymous):

Write the half reaction of HOCl being reduced to Cl-

OpenStudy (aaronq):

(+1)(-2)(+1) (-1) (-2)(+1) HOCl + 2e -> Cl- + OH-

OpenStudy (anonymous):

How does Cl have +1 charge on the left and -1 on the right?

OpenStudy (aaronq):

this is a half reaction, it's being reduced (gaining electrons) from another atom of another compound which is not shown (which would be the other half reaction).

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