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OpenStudy (anonymous):
Write the half reaction of HOCl being reduced to Cl-
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OpenStudy (aaronq):
(+1)(-2)(+1) (-1) (-2)(+1) HOCl + 2e -> Cl- + OH-
OpenStudy (anonymous):
How does Cl have +1 charge on the left and -1 on the right?
OpenStudy (aaronq):
this is a half reaction, it's being reduced (gaining electrons) from another atom of another compound which is not shown (which would be the other half reaction).
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