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Given a \equiv 1 \pmod{7}, b \equiv 2 \pmod{7}, and c \equiv 6 \pmod{7}, what is the remainder when a^{81} b^{91} c^{27} is divided by 7?
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$$a\equiv1\pmod 7\\b\equiv2\pmod7\\c\equiv6\equiv-1\pmod 7$$clearly we have \(a^{81}\equiv1\pmod7,c^{27}\equiv-1\equiv6\pmod7\)
so|dw:1375405293475:dw|
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