Explain how you would find the exact value of 3 over the square root of 8.
\[\frac{ 3 }{ \sqrt{8} }\]
\[\frac{3}{\sqrt{8}}\]?
if you want to write this is simplest radical form, multiply top and bottom by \(\sqrt{2}\)
you get \[\frac{3}{\sqrt{8}}\times \frac{\sqrt{2}}{\sqrt{2}}=\frac{3\sqrt{2}}{\sqrt{16}}=\frac{3\sqrt{2}}{4}\]
Where do you get sqrt(2) from?
although... i have to add, there is nothing more EXACT about either form the second one is written in simplest radical form the first one is not
i got it because it works if you multiply \(8\times 2\) you get a perfect square, namely \(16\)
so \(\sqrt{8}\times \sqrt{2}=\sqrt{16}=4\) and you have no radical left in your denominator
ahh okay. Understandable.
now ask your math teacher the following question: why is \(\frac{3\sqrt{2}}{4}\) more EXACT than \(\frac{3}{\sqrt{8}}\) i would love to know the answer
Good idea! :p
what the question is really asking is "write \(\frac{3}{\sqrt{8}}\) in simplest radical form" which actually has a definition one condition is that there should be no radical in the denominator
lol Satellite, "simplify" lol
well "simplest radical form" actually means something
true
not like "simplify"
i will bet $8 that @Mikeyy1992 math teacher is unclear as to what it means
which is why the problem said "exact"
I will inform exactly what she says (:
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