verify this identity (1-sin x)/(1+sin x)=(sec x-tan x)^2
really?
i did i got stuck
i am guessing multiply the left hand side top and bottom by \(1-\sin(x)\) might be snappy, but maybe not let me try it
yeah that will meet @Loser66 in the middle if you multiply \[\frac{1-\sin(x)}{1+\sin(x)}\times \frac{1-\sin(x)}{1-\sin(x)}\] you get \[\frac{1-2\sin(x)+\sin^2(x)}{\cos^2(x)}\]
yes thats where i got to and i got stuck
oh isnt that what you get when you expand the right hand side?
i am sure it is check it
nope the rhs is sec ^2 x-2secx +tanx+tan^2 x
\[\sec^2(x)-2\tan(x)\sec(x)+\tan^2(x)\]
your plus should be a times in the middle
that is what you get if you divide term by term from here \[\frac{1-2\sin(x)+\sin^2(x)}{\cos^2(x)}\]
oh ok thanks
get with the latex brother alph
OMG @primeralph he got you dude....
@satellite73 Why, why you always got to give away my secrets?
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