verify this identity
(1-sin x)/(1+sin x)=(sec x-tan x)^2
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
really?
OpenStudy (anonymous):
i did i got stuck
OpenStudy (anonymous):
i am guessing multiply the left hand side top and bottom by \(1-\sin(x)\) might be snappy, but maybe not
let me try it
OpenStudy (anonymous):
yeah that will meet @Loser66 in the middle
if you multiply
\[\frac{1-\sin(x)}{1+\sin(x)}\times \frac{1-\sin(x)}{1-\sin(x)}\] you get
\[\frac{1-2\sin(x)+\sin^2(x)}{\cos^2(x)}\]
OpenStudy (anonymous):
yes thats where i got to and i got stuck
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
oh isnt that what you get when you expand the right hand side?
OpenStudy (anonymous):
i am sure it is
check it
OpenStudy (anonymous):
nope the rhs is sec ^2 x-2secx +tanx+tan^2 x
OpenStudy (anonymous):
\[\sec^2(x)-2\tan(x)\sec(x)+\tan^2(x)\]
OpenStudy (anonymous):
your plus should be a times in the middle
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
that is what you get if you divide term by term from here \[\frac{1-2\sin(x)+\sin^2(x)}{\cos^2(x)}\]
OpenStudy (anonymous):
oh ok thanks
OpenStudy (anonymous):
get with the latex brother alph
OpenStudy (anonymous):
OMG @primeralph he got you dude....
OpenStudy (primeralph):
@satellite73 Why, why you always got to give away my secrets?