?
I presume the second hypothesis is meant to be H_A not that they are both null hypotheses?
@agent0smith
sorry, stats really isn't my strong point! but ^^ can hopefully help :)
thank you :)
The only thing I know is that if the p-value is less than the test-statistic (which is usually 0.05 or 0.01) then you reject the null-hypothesis
key takeaway is apply your problem to this: In the above example we thus have: Null hypothesis (H0): The coin is fair; Prob(heads) = 0.5 Observation O: 14 heads out of 20 flips; and p-value of observation O given H0 = Prob(≥ 14 heads or ≥ 14 tails) = 2*(1-Prob(< 14)) = 0.115. The calculated p-value exceeds 0.05, so the observation is consistent with the null hypothesis, as it falls within the range of what would happen 95% of the time were the coin in fact fair. Hence, we fail to reject the null hypothesis at the 5% level. Although the coin did not fall evenly, the deviation from expected outcome is small enough to be consistent with chance. However, had one more head been obtained, the resulting p-value (two-tailed) would have been 0.0414 (4.14%). This time the null hypothesis – that the observed result of 15 heads out of 20 flips can be ascribed to chance alone – is rejected when using a 5% cut-off.
looks like D to me, but I'd just google around and look for a similar question
I think stats sucks. @sarahusher will back me up on that.
DEFINITELY!!
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