Does anyone know of a simpler way to solve the system the substitution method? The following is a problem I have on hand; x-3y=-15 4y-6x=62
multiply the first equation by 6 add this to the second equation, the x's will cancel out
So confirming it will look something like this? (6x)-3y=-15
You have to multiply the whole first equation by 6. first rearrange the order like so (change the order of the second equation): x - 3y = -15 -6x + 4y = 62 Now multiply everything in the first equation by 6, on both sides of the equals sign: 6 ( x - 3y = -15 ) -6x + 4y = 62
x-3y =-15 (1st Eqn) 6(x-3y) = 6(-15) (1st Eqn times 6) =
That makes sense now AgentO... Now will this give me the answer for x or y?
It'll give you y, since it'll eliminate x. 6 ( x - 3y = -15 ) -6x + 4y = 62 becomes 6x - 18y = -90 -6x + 4y = 62 Now add the two equations together.
now when you say add the two equations together, how does that look?
[6x - 18y] = [-90] {-6x + 4y} = {62} [6x - 18y ]+{-6x + 4y } = [-90] +{62} 6x - 18y -6x + 4y = -90 + 62
so is the final answer is (6,2) ?
Adding them vertically is easier imo, since they're already lined up. 6x - 18y = -90 -6x + 4y = 62 -------------- 0 - 14y = -28
That is easier, thx for the tip...
so you've got y=2 right,
sub this into the first equation to get x
So instead of it being x-3y=-15 it would be x-3(2)=-15 to get x?
correct ..
Got it... (-9,2) Thank you both for ur assistance. this was a big help.
that's it \[\boxed{\large\color{red}\checkmark}%unk\]
Awesome.
and you can always check your solution by subbing the solution into the original equations x-3y=-15 4y-6x=62 (x,y)=(-9,2) (-9)-3(2)=-15 4(2)-6(-9)=62 both these should be true
^ learning to check your solutions is a good idea. You never need anyone to check your work (on systems of equations) if you check your own answers.
that's a cool way to check ur work , thx for the tip.
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