What is the exact value of the square root of 24 over 2 the square root of 64.? Simplify if possible.
\[\sqrt{24} \over 2\sqrt{64}\] is what the original equation looks like
64=8*8 24 = 8*3 now you can cancel terms and solve
\[\huge \frac{\sqrt{24}}{2\sqrt{64}}\] where \(\large \sqrt{64}=\sqrt{8^2}=8\) we get, \[\huge \frac{\sqrt{24}}{2 \times 8}\] \[\huge \frac{\sqrt{24}}{16}\]
now simplify it
@glacher
dont do it hes trying to trick you
okay... so it would be \[2\sqrt{6} \over 16\]
its a trap
you are going good. @glacher
thank you @mayankdevnani very much! im usally good at math... but im not to good at Algebra 1
now, \[\huge \frac{2\sqrt{6}}{16}\] and 2 cancel out 16 by 8, we get \[\huge \frac{\sqrt{6}}{8}\]
now simplify it
How can you simplify any further? @mayankdevnani ?
we can write \(\large \sqrt{6}\) as approximate 2.44 now, plug this value , we get \[\huge \frac{\sqrt{6}}{8}=\frac{2.44}{8}=0.305\] This is our approximate answer.
This is how we can simplify it. @skullpatrol
hope you understand. @glacher
I do very much!! @mayankdevnani
good...
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