Question

Is there a chain rule method to differentiate sin(2x), rather than using the conventional 2sinxcosx???

Answer 1

\[\frac{ dsin(2x) }{ dx }=\frac{ dsin(2x) }{ d(2x) }\frac{ d(2x) }{ dx}=\cos(2x)·2\]

Answer 2

I think the way CarlosGP did it is usually considered the "conventional" way.

Answer 3

which is, in fact, the chain rule. Starting with sin(2x)=2sin(x)cos(x) is a bit more complex and unnecessary. It is like finding the derivative of sin(x) through sin(x)=sqrt[(1-cos(2x))/2]

Answer 4

its really awkward to read!

Answer 5

how 2 xpand ur ans vertically??

Answer 6

Oh....got..it!!

Answer 7

TNX