Question

lim (x^2*e^-x)=?
where x tends o infinity

Answer 1

can you use L'Hopital's rule ?

Answer 2

So this is a case where L'Hopital's rule comes in handy. The ratio of two limits is the same as the ratio of the derivative of the two limits, so you can take the derivative of the top and the derivative of the bottom and compare them.

DONT use the quotient rule, you're taking two separate derivatives here.

Answer 3

yes

Answer 4

then you can write that as
x^2/e^x
now take the derivative of numerator and denominator SEPARATELy, what u get ?

Answer 5

ok thank you so much

Answer 6

take x=
1/t
sub in the equation!!

Answer 7

if x tends to infinity....t tends to 0 as x=1/t

Answer 8

is ur q...x^(2*(e^-x)) or sumthing else??