Question

Differentiate
y=((x+1)^3)/x^(3/2)

Answer 1

open (x+1)^3 = x^3 + 3x^2 +3x+1
then time x^(-3/2) to the polynomial , then take derivative term by term. No quotient rule.
Or if you good at quotient rule, just apply.

Answer 2

can u do it using quotient rule...m kinda stuck there!!

Answer 3

what is the quotient rule ?

Answer 4

assume u=(x+1)^3
v=x^3/2
then use the formula.y'={(u').v-(v').u}/v^2

Answer 5

ok, so , what is u'?

Answer 6

derivative of u

Answer 7

m attaching the ans

Answer 8

wich incidentally...m not getin

Answer 9

hopefully I can check! jut post

Answer 10

posted

Answer 11

that's the answer?

Answer 12

yup

Answer 13

why don't you post the whole work?

Answer 14

there's a question.....then this answer....no steps ...no anything!!

Answer 15

why does it mean? it means we have to do it by ourselves, right?

Answer 16

yup....and u want me 2 do it??....and I want sum1 to help me get there!!

Answer 17

I don't want to do it, it's hard to me. But if you do, I will follow and help to check your steps. Is it ok? If we cannot get that answer, then we tag other for help. is it ok?

Answer 18

a'ight

Answer 19

here goes

Answer 20

wut wut... can you calculate u'=?

Answer 21

calculatin

Answer 22

vl post the final ans....u just hav to bring it to the ans form,OK???

Answer 23

I think we have to calculate u', v' from the form of rule
\[\huge \dfrac{u'v-v'u}{v^2}\]where \( u= (x+1)^3\) and \(v = x^{\frac{3}{2}}\)

Answer 24

after calculating, we plug the results into that form to get the answer

Answer 25

xactly

Answer 26

so, you should do it, right? I don't know how to do, hihihi

Answer 27

forgot to write one thing

Answer 28

the numerator 3x/2 where x shud have the xponential power 1/2 ....add that

Answer 29

the v' at the second term of numerator seems not right, friend. (x^(3/2))' = 3/2 x^(3/2-1)= \(\frac{3}{2} x ^{1/2}\)

Answer 30

I just corrected it...in the previous comment

Answer 31

so, your problem is not how to simplify it? and the denominator is x^3, right?

Answer 32

yup
how to get x^5/2 in the denom??

Answer 33

tnx man got...it

Answer 34

I really don't know, friend.

Answer 35

no probs

Answer 36

so sorry.

Answer 37

had to observe a bit....tnx for forcing me to stay on it!!......got the ANSWER

Answer 38

when you have a bad helper like me, you have to do everything by yourself, hihihi..

Answer 39

I am now posting the solution

Answer 40

no need to do that. I am not curious on it. keep it for you only.

Answer 41

no prob....A push was wat I neede...m a bit lethargic..