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Mathematics 7 Online
OpenStudy (anonymous):

x^2+8 over x^2

OpenStudy (anonymous):

@jim_thompson5910 help me please?

jimthompson5910 (jim_thompson5910):

is the problem \[\large \frac{x^2+8}{x^2}\] OR is it \[\large x^2+\frac{8}{x^2}\]

OpenStudy (anonymous):

the first option

jimthompson5910 (jim_thompson5910):

and you want to graph this? or simplify?

jimthompson5910 (jim_thompson5910):

or something else?

OpenStudy (anonymous):

simplify, i dont understand how to :/

OpenStudy (anonymous):

i think its gonna be 8x

jimthompson5910 (jim_thompson5910):

well you can't do much in terms of simplification, but you could break up the fraction like this \[\large \frac{x^2+8}{x^2}\] \[\large \frac{x^2}{x^2}+\frac{8}{x^2}\] what's the the next step?

OpenStudy (anonymous):

i dont know i didnt learn it that way ):

OpenStudy (anonymous):

i dont know i didnt learn it that way ):

jimthompson5910 (jim_thompson5910):

hmm how did you learn it then?

OpenStudy (anonymous):

to find the GCF

jimthompson5910 (jim_thompson5910):

i see

jimthompson5910 (jim_thompson5910):

well the GCF in this case is 1, but that doesn't help much in terms of simplifying

OpenStudy (anonymous):

and they said to cancle the terms out if there was the same on the top and bottom so would it be 8x?

jimthompson5910 (jim_thompson5910):

unfortunately you cannot cancel like that

jimthompson5910 (jim_thompson5910):

you have to break up the fraction first, then you can do simplifications

OpenStudy (anonymous):

oh :/ hmm would it be x(x+8) over x times x ?

jimthompson5910 (jim_thompson5910):

what does x/x simplify to

OpenStudy (anonymous):

0?

OpenStudy (anonymous):

i mean 1

jimthompson5910 (jim_thompson5910):

think about it like this: you have 10 cookies and you distribute them evenly amongst 10 people. How many cookies does each person get?

jimthompson5910 (jim_thompson5910):

yes good, it's 1

jimthompson5910 (jim_thompson5910):

x/x = 1 for any value of x (x can't be zero though)

jimthompson5910 (jim_thompson5910):

so if that's the case, then what is x^2/x^2 ?

OpenStudy (anonymous):

so would the answer be x+8 over x?

jimthompson5910 (jim_thompson5910):

no, what is x^2 over x^2

OpenStudy (anonymous):

1?

jimthompson5910 (jim_thompson5910):

so this means we can say this \[\large \frac{x^2+8}{x^2}\] \[\large \frac{x^2}{x^2}+\frac{8}{x^2}\] \[\large 1+\frac{8}{x^2}\]

OpenStudy (anonymous):

that isnt one of my options ):

jimthompson5910 (jim_thompson5910):

hmm then there's a typo somewhere maybe

jimthompson5910 (jim_thompson5910):

list all your options out

OpenStudy (anonymous):

x+8 over x, x+8 over x^2, 8x and 8

jimthompson5910 (jim_thompson5910):

Maybe it would be better if you took a screenshot of the whole problem (and possible answer choices). Is that possible?

OpenStudy (anonymous):

no );

jimthompson5910 (jim_thompson5910):

have you tried it? you hit prinstcreen, then open up MS paint, save it, then send it

OpenStudy (anonymous):

|dw:1375482382343:dw|

jimthompson5910 (jim_thompson5910):

oh 8x and not 8

jimthompson5910 (jim_thompson5910):

you have a typo at the very top, but that's ok

OpenStudy (anonymous):

oh im sorry );

jimthompson5910 (jim_thompson5910):

its ok

jimthompson5910 (jim_thompson5910):

here's how you simplify

jimthompson5910 (jim_thompson5910):

\[\large \frac{x^2+8x}{x^2}\] \[\large \frac{x(x+8)}{x^2}\] \[\large \frac{x(x+8)}{x*x}\] \[\large \frac{\cancel{x}(x+8)}{\cancel{x}*x}\] \[\large \frac{x+8}{x}\]

OpenStudy (anonymous):

okay thank you !(:

jimthompson5910 (jim_thompson5910):

np

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