What is the fifth term of the given sequence? 1/2x^2y, x^3, (2x^4)/y,....

Question

anonymous · Answer

can you write your function here please

anonymous · Answer

There isn't a function????

anonymous · Answer

the way you've written your question its sorta confusing can u rewrite it please

anonymous · Answer

What is the fifth term of the geometric sequence when a1 =  1/2x^2y,  a2 = x^3,  a3 =  (2x^4)/y

anonymous · Answer

$$a1=\frac{ 1 }{ 2x^{2y} }, a2=x^3,a3=\frac{ 2x^4 }{ y }$$ is this wat u mean?

anonymous · Answer

1/2  * x^2y

anonymous · Answer

im sorry babe i aint getting your question

anonymous · Answer

Never mind then

phi · Answer

it looks like you multiply by
$$ \frac{2x}{y} $$
to get to the next term

phi · Answer

multiply the 3rd term by 2x/y  and then multiply by 2x/y again to get the 5th term.

that means multiply the 3rd term by
$$ \frac{4x^2}{y^2} $$
to get the answer

anonymous · Answer

Sooo... 8x^6 / y^3???

phi · Answer

I have not checked...

$$ \frac{2x^4}{y} \cdot \frac{4x^2}{y^2} $$
that looks like
$$ \frac{8x^6}{y^3} $$

anonymous · Answer

I have done it right then! :D

phi · Answer

yes, looks good