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Mathematics 7 Online
OpenStudy (anonymous):

Finding the slope of a cubic function.

OpenStudy (anonymous):

OpenStudy (anonymous):

clearly the line i want to find has the point (2,1), however what is the desired slope of my line?

OpenStudy (anonymous):

I know that the first derivative gives slope...

OpenStudy (anonymous):

but my function yields a quadratic for the first derivative (???)

OpenStudy (isaiah.feynman):

@mashe try implicit differentiation!

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

wait implicit I don't have xy's together?

OpenStudy (isaiah.feynman):

Yes I just noticed that sorry.

OpenStudy (anonymous):

so i take the limit? lim h---->0 f(a+h) - f(a) / h where a is the x-coordinate of my point?

OpenStudy (wolf1728):

X^3 -6X +5 = 0 taking the derivative: 3X^2 -6 = 0 First derivative can be a quadratic Minimums and Maximums are found where derivative = 0 Solving 3X^2 -6 = 0 by quadratic formula X = sqrt(2) and X = -sqrt(2)

OpenStudy (anonymous):

???

OpenStudy (anonymous):

idk why I get slope through lim h---> 0 giving 18???

OpenStudy (wolf1728):

When X=2, the slope of the function of 3X^2 -6 is 3*2*2 -6 12 -6 =6 Were you working with a formula something like this?

OpenStudy (anonymous):

ohhh so i just take the first derivative and evaluate it at the point

OpenStudy (anonymous):

is that always true in finding the slope of a curve?

OpenStudy (wolf1728):

I believe so. Also, when slope =0 you have a maximum or a minimum.

OpenStudy (anonymous):

thank you so much wolf1728 :-)

OpenStudy (wolf1728):

Glad I could help out. :-)

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