Question

Add and simplify: x+1/x^2+3/4x
11/4x, x ≠ 0
4x+7/4x^2, x ≠ 0
x+4/4x^2, x ≠ 0
7x+4/4x^2, x ≠ 0

Answer 1

help didn't understand the lesson in need of assistants!!

Answer 2

I would help but I don't even get the question. What was the lesson about?

Answer 3

it is about adding and subtracting rational expressions

Answer 4

thanks for trying though

Answer 5

Do you mean \[\frac{ x+1 }{ x^2 } + \frac{ 3 }{ 4x }\]

Answer 6

for teh first one?

Answer 7

ya for the question

Answer 8

oh then maybe i can help after all

Answer 9

ok

Answer 10

my online teacher wasn't helping me so i really am confused on this lesson

Answer 11

if you multiply \[\frac{ 3 }{ 4x }\] by x, you get \[\frac{ 3x }{ 4x^2 }\] which will simplify your question to \[\frac{ x+1 }{ x^2 } + \frac{ 3x }{ 4x^2 }\] (since \[\frac{ 3 }{ 4x } = \frac{ 3x }{ 4x^2 }\] the x cancel out on the right hand side)

we have to now multiply the top and bottom of \[\frac{ x+1}{ x^2 }\] by 4 to get the same denominator. This will give us \[\frac{ 4(x+1) }{ 4x^2 }\]
Now the question becomes
\[\frac{ 4(x+1) }{ 4x^2 }\ + \frac{ 3x }{ 4x^2 }\]
which is equals to
\[\frac{ 4(x+1) +3x }{ 4x^2 }\]
which gives us the answer
\[\frac{ 7x+4 }{ 4x^2 }\]

Hope you get it...