3x+2y=4 x+3y=-1 solve using addition
are you sure you use addition? don't you mean substitution or elimination?
@amyamanda
it says addition
then just add the two systems together. what is 3x+x?
4x
and 2y+3y? Good!, btw
5y
then 4+(-1)?
3
right so put it all together and you get... :)
so 4x+5y=3
right! good job :)
r u sure that's right, that doesn't seem right
why? is it not a choice, because as you solve by addition, addition means to add, so this should be your answer
unless i have misunderstood your question...
"Addition" does not stop you from multiplying by a + or - factor before you add. Essentially it would be elimination.
? I'm confused
so you would use elimination? hmmm i must have learned it differently
@mathmate does that mean that 4x+5y=3 is incorrect?
As far as I know, I would not accept 4x+5y=3 as the solution to a system of equations.
ok @mathmate could you please break down step by step for me
right i was just confused when she said solve by addition. However for this case, substitution seems more applicable
or is it just me? idk
The solution set to a system of two equations would typically (but not always) be S=(x,y) where x,y are numbers.
Yes, substitution and elimination are both feasible.
However, elimination is a kind of addition, so that's what I suggest, not because it is simpler.
ok how do I use elimination?
Elimination means that you multiply one or both equations with certain numbers so that the coefficients of a variable are identical. For example, if you multiply the second equation by -3, you will get 3x+2y=4 -3x-9y=3 Now you need to add the two equations and solve for y because the x's will cancel out when you ADD.
y=-1
@mathmate y=-1
Very good, now all you have to do is to put y=-1 into one of the original equations and solve for x.
x=2
independent equation because it only has one solution
Good observation! Now the last step (whenever you solve a system of equations) is to put back the solution set into the original equations and see if they "work". What is your solution set?
6-2=4 2-3=-1
Perfect, they match. The solution set is S=(2,-1) i.e. x=2, y=-1, is that ok?
yup
ty!
yw!
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