~~Medal and fanning whoever helps me thank you :)!!!~~ create two different “answers” (and the questions that accompany them)
Of what ?
this is an example at @FilthyMcNasty x2 + 6x + 5 is the product of these two binomials. Expected Question from Contestant: What is (x + 5)(x + 1)?
So you want the answer to (x + 5)(x + 1)?
Oh no I need 2 other made up questions with the answer @FilthyMcNasty
oh ok. Hold up
x² + 5x + 6, (x + 3)(x + 2) ; 15x²-11x-14, (3x+2)(5x-7)
x² + 5x + 6, is the product of what two binomials? -Contestant: What is (x + 3)(x + 2) 15x²-11x-14, is the product of what two binomials? -Contestant: What is (3x+2)(5x-7)
Thank you so much @FilthyMcNasty but could you explain step by step your answers
x² + 5x + 6 -Find 2 numbers whose product is 6, yet add up to 5x: 3x & 2x x² + 2x + 3x + 6 (x² + 2x) + (3x + 6) x(x+2) +3(x+2) (x+3)(x+2) 15x²-11x-14 (Multiply 1st and last terms mentally:210) -Find 2 numbers whose product is 210, yet add up to -11x: -21x & 10x 15x²-21x + 10x -14 (15x²-21x) + (10x -14) 3x(5x-7)+2(5x-7) (3x+2)(5x-7)
Thanks so much bro your name btw funny as hell
lol & no problem
:D @SOS101
thxs
Wait @filthymcnasty
@Mertsj
@Mertsj could you help creating one please
@Mertsj
@Mertsj please help us :(
What is the question?
Create two different “answers” (and the questions that accompany them) similar to the ones up there @Mertsj
x^2+7x+12 What is (x+3)(x+4)
x^2-7x+12 What is (x-4)(x-3)
x^2+20x+100 What is (x+10)(x+10)
x^2-x-6 What is (x-3)(x+2)
Wait @Mertsj can you explain how you got the 2nd one how you got your answer like the way filthy did it
Do you know how to factor trinomials?
Kind of but i need an explanation to check my understanding
@Mertsj
Pick two numbers
@Jamierox4ev3r
Huh what do you mean @Mertsj
x² + 5x + 6 -Find 2 numbers whose product is 6, yet add up to 5x: 3x & 2x x² + 2x + 3x + 6 (x² + 2x) + (3x + 6) x(x+2) +3(x+2) (x+3)(x+2) could you do it in an explanation like that for your second one @celecity
@Helpmeplease99
@ash2326 can you help us?
Yeah, ok I'll also explain how a quadrati trinomial is factored
oops *quadratic
ok thxs
Suppose you have a quadratic expression \[ax^2+bx+c=0\] find the product of a and c \[ac\] Find factors of ac such that they add up to become b then you have to write b in terms of those factors, it's almost over. Do you get this? I'll explain with an example
Suppose we have x^2+7x+6 First step multiply a and c \[a=1, c=6, ac=6\] Write down factors of ac such that they add up to b \[b=7\] \[ac=6\] factors are 6 and 1 \[check=6+1=7 \] write b in terms of those factors \[x^2+(6+1)x+6\] \[x^2+6x+x+6\] \[x(x+6)+1(x+6)\] bring (x+6) out \[(x+6)(x+1)\] and it's factored
Do you get this?
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