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Mathematics 15 Online
OpenStudy (anonymous):

~~Medal and fanning whoever helps me thank you :)!!!~~ create two different “answers” (and the questions that accompany them)

OpenStudy (anonymous):

Of what ?

OpenStudy (anonymous):

this is an example at @FilthyMcNasty x2 + 6x + 5 is the product of these two binomials. Expected Question from Contestant: What is (x + 5)(x + 1)?

OpenStudy (anonymous):

So you want the answer to (x + 5)(x + 1)?

OpenStudy (anonymous):

Oh no I need 2 other made up questions with the answer @FilthyMcNasty

OpenStudy (anonymous):

oh ok. Hold up

OpenStudy (anonymous):

x² + 5x + 6, (x + 3)(x + 2) ; 15x²-11x-14, (3x+2)(5x-7)

OpenStudy (anonymous):

x² + 5x + 6, is the product of what two binomials? -Contestant: What is (x + 3)(x + 2) 15x²-11x-14, is the product of what two binomials? -Contestant: What is (3x+2)(5x-7)

OpenStudy (anonymous):

Thank you so much @FilthyMcNasty but could you explain step by step your answers

OpenStudy (anonymous):

x² + 5x + 6 -Find 2 numbers whose product is 6, yet add up to 5x: 3x & 2x x² + 2x + 3x + 6 (x² + 2x) + (3x + 6) x(x+2) +3(x+2) (x+3)(x+2) 15x²-11x-14 (Multiply 1st and last terms mentally:210) -Find 2 numbers whose product is 210, yet add up to -11x: -21x & 10x 15x²-21x + 10x -14 (15x²-21x) + (10x -14) 3x(5x-7)+2(5x-7) (3x+2)(5x-7)

OpenStudy (anonymous):

Thanks so much bro your name btw funny as hell

OpenStudy (anonymous):

lol & no problem

OpenStudy (anonymous):

:D @SOS101

OpenStudy (anonymous):

thxs

OpenStudy (anonymous):

Wait @filthymcnasty

OpenStudy (anonymous):

@Mertsj

OpenStudy (anonymous):

@Mertsj could you help creating one please

OpenStudy (anonymous):

@Mertsj

OpenStudy (anonymous):

@Mertsj please help us :(

OpenStudy (mertsj):

What is the question?

OpenStudy (anonymous):

Create two different “answers” (and the questions that accompany them) similar to the ones up there @Mertsj

OpenStudy (mertsj):

x^2+7x+12 What is (x+3)(x+4)

OpenStudy (mertsj):

x^2-7x+12 What is (x-4)(x-3)

OpenStudy (mertsj):

x^2+20x+100 What is (x+10)(x+10)

OpenStudy (mertsj):

x^2-x-6 What is (x-3)(x+2)

OpenStudy (anonymous):

Wait @Mertsj can you explain how you got the 2nd one how you got your answer like the way filthy did it

OpenStudy (mertsj):

Do you know how to factor trinomials?

OpenStudy (anonymous):

Kind of but i need an explanation to check my understanding

OpenStudy (anonymous):

@Mertsj

OpenStudy (mertsj):

Pick two numbers

OpenStudy (anonymous):

@Jamierox4ev3r

OpenStudy (anonymous):

Huh what do you mean @Mertsj

OpenStudy (anonymous):

x² + 5x + 6 -Find 2 numbers whose product is 6, yet add up to 5x: 3x & 2x x² + 2x + 3x + 6 (x² + 2x) + (3x + 6) x(x+2) +3(x+2) (x+3)(x+2) could you do it in an explanation like that for your second one @celecity

OpenStudy (anonymous):

@Helpmeplease99

OpenStudy (anonymous):

@ash2326 can you help us?

OpenStudy (ash2326):

Yeah, ok I'll also explain how a quadrati trinomial is factored

OpenStudy (ash2326):

oops *quadratic

OpenStudy (anonymous):

ok thxs

OpenStudy (ash2326):

Suppose you have a quadratic expression \[ax^2+bx+c=0\] find the product of a and c \[ac\] Find factors of ac such that they add up to become b then you have to write b in terms of those factors, it's almost over. Do you get this? I'll explain with an example

OpenStudy (ash2326):

Suppose we have x^2+7x+6 First step multiply a and c \[a=1, c=6, ac=6\] Write down factors of ac such that they add up to b \[b=7\] \[ac=6\] factors are 6 and 1 \[check=6+1=7 \] write b in terms of those factors \[x^2+(6+1)x+6\] \[x^2+6x+x+6\] \[x(x+6)+1(x+6)\] bring (x+6) out \[(x+6)(x+1)\] and it's factored

OpenStudy (ash2326):

Do you get this?

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