How do you find the maclaurin series for 10^x?
\[\sum_{n=1}^{\infty}\frac{f^n(0)x^n}{n!}\]
start taking the derivatives
Like f'(x) = x10^(x-1)?
f^1 = ln(10)*10^x f^2 = ln^2(10)10^x .... so the derivatives at x = 0 are ln(10) ln(10)^2 ln(10)^3 so the maclorian is \[\sum_{n=1}^{\infty}\frac{(ln(10)x)^n}{n!}\]
No, that's not correct. The power rule applies for \[\frac{ d }{ dx }x^n\] but \[\frac{ d }{ dx } 10^x\] is something quite different! Learn how to differentiate exponential functions.
no derivative of a^x = ln(a)*a^x
don't worry everyone forgets how to differentiate that....common mistake to confuse it with a power rule.
Thanks, so then, thats it?
that was confusing;p
d/dx e^x is the same ln(e)*e^x = 1*e^x = e^x
so proving a^x with e^x does not help:P
just memorize it
I don't think I can forget it now, thanks!
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