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Mathematics 14 Online
OpenStudy (anonymous):

f(x)=e^2x. show the antiderivative and show its confirmation

OpenStudy (agent0smith):

\[\Large f(x) = e^{2x}\] Derivative of e^[f(x)] is f'(x)e^[f(x)] So all you need to do, is multiply e^2x by the derivative of 2x.

OpenStudy (agent0smith):

\[\huge \frac{ d }{ dx} e^{f(x)} = f'(x) * e^{f(x)}\]

OpenStudy (anonymous):

Thanks what about e^x +2?

OpenStudy (agent0smith):

\[\Large e^x + 2\]or \[\Large e^{x +2}\] For the first, just differentiate both parts... derivative of e^x is e^x, derivative of 2 is zero For the second, use the rule i gave above.

OpenStudy (anonymous):

its the first one.

OpenStudy (anonymous):

but i'm suppose to show the antiderivative right? not just the derivative?

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