Question

A body was found at 6.am outdoors on a day when the temperature was 50 degrees. The medical examiner found the temperature of the body to be 66 degrees. What was the approximate time of death? Use newtons law of cooling, with k= 0.1947
T(t) = Ta + (To - Ta)e^kt

Answer 1

Please help

Answer 2

I'm a little tired and in need of sleep here, sorry i can't do a step by step guide, but i would try and find out rate of change of temp per hr from 66 deg to 50 degs, and take it from the 6am.

Answer 3

Thanks soo much

Answer 4

np,hope I helped

Answer 5

Would it be 5 am, 2 am, 3 am, or midnight

Answer 6

i still need help

Answer 7

hmm give me a few mins see if i can work it out for you, very tired here sorry

Answer 8

okay thanks
sorry but really need help

Answer 9

can you tell mw which variables the t0,ta are please ? i'm guessing Ta = time aprox

Answer 10

to=intial temp
ta=ambient temp

Answer 11

thx

Answer 12

np

Answer 13

tt = 50 + (16)e(^-0.1947 x change in time)
=> tt -50 /16 = e(^-0.1947 x change in time)
=> change in time = ln (tt - 50/16) / -0.1947 (k)

hmm without a change in time, or a temp of body at time of death I don't see how to do this, very sorry :C I did find a useful tool that may help though
http://www.endmemo.com/physics/coollaw.php

Answer 14

but if i just cheat here :} by putting in 0.5 hrs as time diff i got 69 degs as final, only 3 of the 66 hmm..

Answer 15

so

Answer 16

time diff of 0.2 hrs gets you 66.6 final temp btw

Answer 17

5 am?

Answer 18

yeah I think so :)

Answer 19

damnit sorry i know I know can be more helpful with sleep

Answer 20

it was midnight

Answer 21

that was the anser

Answer 22

if you sub in 6 hrs time diff, the final temp doesn't give me 66 degs :L

Answer 23

idk thats what it said

Answer 24

ahh , forgot i swapped the sign :D

Answer 25

yeah now if i sub in -6 :P not 6 you get final temp of, you guess it: 66 degs,s o midnight is right :}

Answer 26

sorry lol